Мат в 2 хода
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1...Kd1[a]/Nf1[c]/Ng2[d]/Ng4 2.Qa1#[A]
1...Kf1[b]/Nd1[e]/Nc2[f] 2.Qg1#[B]
1...Nf5/Nd5/Nc4 2.Qg1#[B]/Qa1#[A]
1.Qg5? zz
1...Kf1[b]/Nd1[e] 2.Qg1#[B]
1...Nf1[c]/Ng2[d]/Ng4 2.Qc1#[C]
1...Nf5/Nd5/Nc2[f]/Nc4 2.Qg1#[B]/Qc1#[C]
but 1...Kd1[a]!
1.Qa7[D]? zz
1...Kd1[a]/Nf1[c] 2.Qa1#[A]
1...Nf5/Ng2[d]/Ng4/Nd5/Nc4 2.Qa1#[A]/Qg1#[B]
1...Nd1[e]/Nc2[f] 2.Qg1#[B]
but 1...Kf1[b]!
1.Qd4[E]? zz
1...Kd1[a]/Nf1[c] 2.Qa1#[A]
1...Nf5/Ng2[d]/Ng4/Nd5/Nc4 2.Qg1#[B]/Qa1#[A]
1...Nd1[e]/Nc2[f] 2.Qg1#[B]
but 1...Kf1[b]!
1.Kxe3? (2.Qg1#[B]/Qa1#[A])
1...Kf1[b] 2.Qg1#[B]
but 1...Kd1[a]!
1.Qg3+??
1...Kf1[b] 2.Qg1#[B]/Qf2#
but 1...Kd1[a]!
1.Qc3+??
1...Kd1[a] 2.Nf2#/Qd2#/Qa1#[A]
but 1...Kf1[b]!
1.Qb7! zz
1...Kd1[a]/Nf1[c]/Ng2[d]/Nd5 2.Qb1#[F]
1...Kf1[b]/Nd1[e] 2.Qh1#[G]
1...Nf5/Ng4/Nc2[f]/Nc4 2.Qb1#[F]/Qh1#[G]
Как Вы оцените задачу?
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