Мат в 2 хода
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1...Kxb4[a]/Bxb6[d] 2.Be7#[A]
1...Kxb6[b]/Bxb4[c] 2.Bd4#[B]
1.Kc7? (2.Be7#[A]/Nd3#[C])
1...Kxb4[a] 2.Be7#[A]
1...Bxb4[c] 2.Bd4#[B]/Be7#[A]
but 1...Bxb6+[d]!
1.Bd3[D]? zz
1...Kxb4[a]/Bxb6[d] 2.Be7#[A]
1...Bxb4[c] 2.Bd4#[B]
but 1...Kxb6[b]!
1.Be2[E]? zz
1...Kxb4[a]/Bxb6[d] 2.Be7#[A]
1...Bxb4[c] 2.Bd4#[B]
but 1...Kxb6[b]!
1.Bf1[F]? zz
1...Kxb4[a]/Bxb6[d] 2.Be7#[A]
1...Bxb4[c] 2.Bd4#[B]
but 1...Kxb6[b]!
1.Bxc3? (2.Na4#[G])
1...Kxb6[b]/Bxb4[c] 2.Bd4#[B]
but 1...Bxb6[d]!
1.Bd8? (2.Nd3#[C])
1...Kxb4[a]/Bxb6[d] 2.Be7#[A]
but 1...Bxb4[c]!
1.N4d5? (2.Bd4#[B]/Be7#[A])
but 1...Bxb6[d]!
1.N6d5? (2.Bd4#[B]/Be7#[A])
1...Bc7/Bd8 2.Bd4#[B]
but 1...Bxb4[c]!
1.e4[H]! zz
1...Kxb4[a] 2.Be7#[A]
1...Kxb6[b] 2.Bd4#[B]
1...Bxb4[c] 2.Na4#[G]
1...Bxb6[d] 2.Nd3#[C]
Как Вы оцените задачу?
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