Мат в 2 хода
|
1...Bxe1[a]/Bxc3[c] 2.Qxe3#[A]
1...Bc1[b] 2.Nf2#[B]
1.Kxf6? zz
1...Bxe1[a] 2.Qxe3#[A]
1...Bc1[b] 2.Nf2#[B]
but 1...Bxc3+[c]!
1.Kf4?? zz
1...Bxe1[a]/Bxc3[c] 2.Qxe3#[A]
1...Bc1[b] 2.Nf2#[B]
but 1...f5!
1.Kg4?? zz
1...Bxe1[a]/Bxc3[c] 2.Qxe3#[A]
1...Bc1[b] 2.Nf2#[B]
but 1...f5+!
1.Kg6?? zz
1...Bxe1[a]/Bxc3[c] 2.Qxe3#[A]
1...Bc1[b] 2.Nf2#[B]
but 1...f5!
1.Ke6?? zz
1...Bxe1[a]/Bxc3[c] 2.Qxe3#[A]
1...Bc1[b] 2.Nf2#[B]
but 1...f5!
1.Bf2?? zz
1...Be1[a]/Bxc3[c] 2.Qxe3#[A]
but 1...Bc1[b]!
1.Bg3?? zz
1...Be1[a]/Bxc3[c] 2.Qxe3#[A]
but 1...Bc1[b]!
1.Bh4?? zz
1...Be1[a]/Bxc3[c] 2.Qxe3#[A]
but 1...Bc1[b]!
1.Bxd2?? (2.Qxe3#[A])
but 1...Kxd2!
1.Qf2?? zz
1...Bxe1[a] 2.Bxc2#[C]/Qxc2#/Qxe3#[A]
1...Bc1[b] 2.Bxc2#[C]/Qxc2#
1...Bxc3[c] 2.Qxe3#[A]
1...e2 2.Qd4#
but 1...exf2!
1.Qg2?? zz
1...Bxe1[a]/Bc1[b] 2.Bxc2#[C]/Qxc2#
1...e2 2.Qe4#/Qd5#
but 1...Bxc3[c]!
1.Nxe3! zz
1...Bxe1[a] 2.Nf1#[E]
1...Bc1[b] 2.Bxc2#[C]
1...Kxc3/Bxc3[c] 2.Nxc2#[D]
1...Bxe3 2.Qf1#
Как Вы оцените задачу?
|