Мат в 2 хода
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1...Kf4[a]/Kd4[c] 2.Qe4#[A]
1...Kxf6[b] 2.Qh8#[B]
1...Kxd6[d] 2.Qb8#[C]
1.d7? zz
1...Kf4[a]/Kd4[c] 2.Qe4#[A]
1...Kd6[d] 2.Qb8#[C]
but 1...Kxf6[b]!
1.Rh6? zz
1...Kd4[c] 2.Qe4#[A]
1...Kxd6[d] 2.Qb8#[C]
but 1...Kf4[a]!
1.b3? zz
1...Kf4[a] 2.Qe4#[A]
1...Kxf6[b] 2.Qa1#/Qh8#[B]
1...Kxd6[d] 2.Qb8#[C]
but 1...Kd4[c]!
1.f7? zz
1...Kf4[a]/Kd4[c] 2.Qe4#[A]
1...Kf6[b] 2.Qh8#[B]
but 1...Kxd6[d]!
1.Ng6+[D]??
1...Kxf6[b] 2.Qf8#/Qh8#[B]
1...Kd4[c] 2.Qe4#[A]
but 1...Kxd6[d]!
1.Ng8?? zz
1...Kf4[a]/Kd4[c] 2.Qe4#[A]
but 1...Kxd6[d]!
1.Nc8?? zz
1...Kf4[a]/Kd4[c] 2.Qe4#[A]
but 1...Kxf6[b]!
1.Qb7?? zz
1...Kf4[a]/Kd4[c] 2.Qe4#[A]
1...Kxd6[d] 2.Qb8#[C]
but 1...Kxf6[b]!
1.Qc6?? zz
1...Kf4[a]/Kd4[c] 2.Qe4#[A]
but 1...Kxf6[b]!
1.Qd5+??
1...Kf4[a] 2.Qe4#[A]
but 1...Kxf6[b]!
1.Qe4+[A]??
1...Kxd6[d] 2.Qf4#
but 1...Kxf6[b]!
1.Qf3?? zz
1...Kxf6[b] 2.Qc3#[E]
1...Kd4[c] 2.Qf4#/Qc3#[E]/Qe4#[A]
1...Kxd6[d] 2.Qf4#/Qxg3#[F]
but 1...gxf3!
1.Bxg4+??
1...Kf4[a] 2.Qf3#
1...Kxf6[b] 2.Qf8#/Qh8#[B]
1...Kxd6[d] 2.Qb8#[C]/Qd8#/Qc6#
but 1...Kd4[c]!
1.Qa3! zz
1...Kf4[a] 2.Ng6#[D]
1...Kxf6[b]/Kd4[c] 2.Qc3#[E]
1...Kxd6[d] 2.Qxg3#[F]
Как Вы оцените задачу?
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