Решение шахматной задачи №40827
Мат в 2 хода |
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...c4[f] 2.Ra5#[D]
1...dxc2[g]/d2[h] 2.Ke2#[E]
1.Bc7? zz
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...dxc2[g]/d2[h] 2.Ke2#[E]
but 1...c4[f]!
1.Rc1? zz
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...c4[f] 2.Ra5#[D]
1...d2[h] 2.Ke2#[E]
but 1...c2[g]!
1.Rxc3? (2.Rxd3#)
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Nf4[e] 2.Kxf4#[C]
1...c4[f] 2.Ra5#[D]
but 1...Nxc3!
1.Rxf2? zz
1...Ne3[a]/Nb2[b] 2.Kxe3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...c4[f] 2.Ra5#[D]
1...d2[h] 2.Ke2#[E]
1...Nxf2 2.Kxf2#
but 1...c2[g]!
1.Rb4? zz
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...c4[f] 2.Rb5#[G]
1...dxc2[g]/d2[h] 2.Ke2#[E]
but 1...cxb4!
1.Rf4? zz
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c]/Ng7[d] 2.Kxg3#[B]
1...c4[f] 2.Rd4#[H]
1...dxc2[g]/d2[h] 2.Ke2#[E]/Bc4#[I]
but 1...Nxf4[e]!
1.Nc6?? (2.Ne7#)
but 1...Kxc6!
1.Nc8?? (2.Ne7#)
but 1...Kc6!
1.Bd8?? zz
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...dxc2[g]/d2[h] 2.Ke2#[E]
but 1...c4[f]!
1.Ba5?? zz
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...dxc2[g]/d2[h] 2.Ke2#[E]
but 1...c4[f]!
1.Ne3+[F]??
1...Ke5 2.Nc6#/Re4#
but 1...Nxe3[a]!
1.Rca2?? zz
1...Ne3[a] 2.Kxe3#[A]
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Ng3[c] 2.Kxg3#[B]
1...Ng7[d] 2.Kf4#[C]/Kg3#[B]
1...Nf4[e] 2.Kxf4#[C]
1...c4[f] 2.Ra5#[D]
1...d2[h] 2.Ke2#[E]
but 1...c2[g]!
1.Rd2?? (2.Rxd3#)
1...Nb2[b] 2.Kxf2#/Ke3#[A]
1...Nf4[e] 2.Kxf4#[C]
1...c4[f] 2.Ra5#[D]
but 1...cxd2[h]!
1.Re4! zz
1...Ne3[a]/Nb2[b] 2.Nxe3#[F]
1...Ng3[c]/Ng7[d]/Nf4[e] 2.Nxf6#[J]
1...c4[f] 2.Rd4#[H]
1...dxc2[g]/d2[h] 2.Bc4#[I] |