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Решение шахматной задачи №83209

Шахматная задача №83209
Мат в 2 хода
1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bc6#[B] 1...Kc2[c] 2.Ba4#[C] 1...Kxc4[d] 2.Be6#[D] 1.Qg5? zz 1...Ke2[a] 2.Qe3#[F] 1...Kxe4[b] 2.Qd5#[E]/Qe3#[F] 1...Kd4/Kxc4[d] 2.Qd5#[E] but 1...Kc2[c]! 1.Qb6? zz 1...Ke2[a]/Kxe4[b] 2.Qe3#[F] 1...Kc2[c] 2.Qb1#[G] but 1...Kxc4[d]! 1.Qa5? zz 1...Kd4/Kxe4[b] 2.Qd5#[E] 1...Kc2[c] 2.Qc3#[H] 1...Kxc4[d] 2.Qd5#[E]/Qc3#[H] but 1...Ke2[a]! 1.Be6+[D]? 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Qd5#[E] but 1...Kc2[c]! 1.Re5? zz 1...Ke2[a] 2.Bg4#[A] 1...Kc2[c] 2.Ba4#[C] 1...Kxc4[d] 2.Be6#[D] but 1...Kd4! 1.Rc5? zz 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bc6#[B] 1...Kc2[c] 2.Ba4#[C] but 1...Kd4! 1.Kb1? zz 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bc6#[B] 1...Kxc4[d] 2.Be6#[D] but 1...Kd4! 1.Kb2? zz 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bc6#[B] 1...Kxc4[d] 2.Be6#[D]/Bb5# but 1...Kd4! 1.R1xh2? zz 1...Kxe4[b] 2.Bc6#[B] 1...Kxc4[d] 2.Be6#[D] but 1...Kd4! 1.Bf5+?? 1...Ke2[a] 2.Bg4#[A] 1...Kxc4[d] 2.Be6#[D]/Qd5#[E] but 1...Kc2[c]! 1.Bg4+[A]?? 1...Kxe4[b] 2.Re1#/Nf2#[I]/Nc3#/Qd5#[E] 1...Kxc4[d] 2.Be6#[D]/Qd5#[E] but 1...Kc2[c]! 1.Bh3+?? 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bg2#/Qd5#[E] 1...Kxc4[d] 2.Be6#[D]/Qd5#[E] but 1...Kc2[c]! 1.Be8+?? 1...Kxe4[b] 2.Bc6#[B]/Qd5#[E] 1...Kc2[c] 2.Ba4#[C] 1...Kxc4[d] 2.Bf7#/Qd5#[E] but 1...Ke2[a]! 1.Bc6+[B]?? 1...Kc2[c] 2.Ba4#[C] 1...Kxc4[d] 2.Qd5#[E] but 1...Ke2[a]! 1.Bb5+?? 1...Kxe4[b] 2.Bc6#[B]/Qd5#[E] 1...Kc2[c] 2.Ba4#[C] but 1...Ke2[a]! 1.Ba4+[C]?? 1...Kxe4[b] 2.Bc6#[B]/Qd5#[E] 1...Kxc4[d] 2.Qd5#[E] but 1...Ke2[a]! 1.Bc8+?? 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bb7#/Qd5#[E] 1...Kxc4[d] 2.Be6#[D]/Qd5#[E] but 1...Kc2[c]! 1.Be3?? zz 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bc6#[B] 1...Kc2[c] 2.Ba4#[C] 1...Kxc4[d] 2.Be6#[D] but 1...h6! 1.Ra5?? zz 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bc6#[B] 1...Kc2[c] 2.Ba4#[C] 1...Kxc4[d] 2.Be6#[D] but 1...Kd4! 1.Ka2?? zz 1...Ke2[a] 2.Bg4#[A] 1...Kxe4[b] 2.Bc6#[B] 1...Kc2[c] 2.Ba4#[C] 1...Kxc4[d] 2.Be6#[D]/Bb5# but 1...Kd4! 1.Qf6! zz 1...Ke2[a] 2.Qf1#[J] 1...Kxe4[b] 2.Nf2#[I] 1...Kc2[c]/Kxc4[d] 2.Qc3#[H]

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